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Mathematics Probability of combined events
Class 10 Advanced About 20 min Premium

Two cards in a row: putting back or keeping out

Draw two cards one after the other and find the chance that both are aces, both hearts or both red: once putting the first card back, once keeping it out. A probability tree shows why the second draw changes.

Core concept

P(A and B) = P(A) × P(B after A): with the card put back the draws are independent; kept out, the second depends on the first

Topic: Probability of combined events

A pack of playing cards has 52 cards in four suits: spades ♠ and clubs ♣ are black, and hearts ♥ and diamonds ♦ are red. Each suit has 13 cards: the ace, the number cards 2 to 10, and three face cards, the jack, the queen and the king. Draw a card, then draw another. If you put the first card back and shuffle, the pack is the same for the second draw: the two draws are independent, and P(both) = P(first) × P(second) with the same probability: How likely something is to happen, from 0 (impossible) to 1 (certain). All key words twice. If you keep the first card out, the pack has only 51 cards, and if the first card was an ace there are only 3 aces left. The second draw depends on the first. A probability tree shows each draw as a branch: multiply along the branches to find the chance of both.

Key words explained

What you will learn

  • Draw a probability tree for two cards drawn one after the other.
  • Find P(both) for independent draws, with the card put back.
  • Find P(both) for dependent draws, with the card kept out, and explain the difference.

Before you start

  • Find the probability of a single event when drawing a card.
  • Multiply fractions.

Materials

  • A pack of 52 playing cards (jokers taken out)

Equipment

  • Paper and a pencil for the probability tree

Procedure

  1. Choose an event and whether the first card is put back.
  2. Read the two branches of the tree and multiply them to find P(both).
  3. Compare two aces, two hearts and two red cards with and without putting the first card back.

How this simulation is simplified

  • The pack has 52 cards and no jokers, and it is shuffled so every card is equally likely.
  • When the first card is put back, the pack is shuffled again before the second draw.
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